NEET 준비: 효과적인 문제 해결 전략

### NEET 지망생을 위한 문제 풀이 마스터하기
* 👋 많은 NEET 지원자들은 수업에서 개념을 이해한 후에도 **혼자서 문제를 푸는 데 어려움**을 겪습니다.
* 📚 연사는 **11학년과 12학년 때 비슷한 도전에 직면했던 개인적인 경험**을 공유하며 **효과적인 문제 해결이 NEET 성공에 매우 중요**하다고 강조합니다.
* 📝 문제에 효과적으로 접근하려면 **모든 관련 공식을 파악**하고, 그 적용을 이해하고, 그 이면의 개념을 해독하는 것이 필수적입니다.
* 📖 문제를 푸는 첫 번째 단계는 문제를 대충 훑어보지 말고 주의 깊게 읽고 **관리 가능한 부분으로 세분화**하는 것입니다.
* 🔍 핵심 정보를 강조 표시하고 주어진 내용을 적어두면 **학생들은 문제를 더 잘 시각화**하고 해결해야 할 사항을 파악할 수 있습니다.
* 📊 이 동영상에서는 올바른 공식을 사용하고 주어진 데이터를 이해하여 **평균 속도와 속도를 계산하는 방법**에 대해서도 설명합니다.
* 🔗 NEET 대비를 위한 엘리트 플랜과 같은 추가 리소스에서는 학생들이 시험에서 우수한 성적을 거둘 수 있도록 **맞춤형 연습 문제와 복습 자료**를 제공합니다.
* 💡 연사는 공식을 암기할 때 **플래시카드를 꾸준히 연습**하고 사용할 것을 권장하며, 올바른 접근 방식을 통해 학생들이 **문제 해결 능력을 크게 향상**시킬 수 있다고 강조합니다.

### 물리학 개념 이해 변위, 마찰 및 에너지 손실
* 📏 첫 번째 시나리오에서 변위, 시간 및 가속도와 함께 공식을 사용하면 **변위가 0미터**가 되며, 이는 물체가 **3미터 앞으로 이동했다가 뒤로 이동**한 후 초기 위치로 돌아갔음을 나타냅니다.
* ⏳ 이 동작에 걸린 총 시간은 **3초**로, 평균 속도는 **초당 1미터**로 객관식 문제에서 선택지를 없애는 데 도움이 됩니다.
* 🔍 평균 속도를 결정하려면 총 이동 거리인 **9미터**를 고려해야 하므로 평균 속도는 **초당 3미터**가 됩니다.
* ⚖ 다음 문제는 매끄러운 경사면에 블록이 있는 경우로, **블록이 거리 d를 이동한 후 정지**한 후 마찰 계수를 구해야 합니다.
* 📉 마찰로 인해 발생하는 일과 손실되는 에너지가 같다는 것을 이해하고, **블록이 경사면을 따라 이동하면서 초기 운동 에너지가 위치 에너지로 변환되는 일-에너지 원리**를 적용합니다.
* 📐 초기 운동 에너지는 **mgh**로 표현되며, 높이를 거리 x와 각도 θ로 대입하면 마찰 계수를 구하는 데 필요한 방정식을 도출할 수 있습니다.
* 🔋 마지막으로 커패시터가 있는 회로의 에너지 손실을 분석할 때는 **커패시터에 저장된 초기 에너지를 계산**하고, 커패시터를 병렬로 연결한 후 **최종 에너지를 도출**하여 에너지 손실 비율을 구합니다.
* 📊 각 요구 사항에 체계적으로 집중함으로써 **물리 문제를 효과적으로 해결**하고 관련 개념에 대한 이해를 높일 수 있습니다.

NEET 지원자들은 수업 시간에 개념을 잘 이해했음에도 불구하고 문제를 푸는 데 어려움을 겪는 경우가 많습니다.

Hey champs, welcome back to a new video! No matter which video I open on my channel, there is one comment that you all make under every video, and that is, Brother, we can't solve questions. We understand well in class, but when we sit down to do it ourselves, we just can't seem to tackle the questions. We don't even get a sense of what is being asked. Brother, we can form questions, but it takes us a lot of time. These difficulties are something that almost every NEET aspirant faces at some point.

आपके इस नीट के फेज में आता ही आता है। मैंने भी यह चीज़ फेस की है, इसलिए मैं अच्छे से रिलेट कर सकता हूं। जब मैं अपने 11वीं और 12वीं में था, तो मुझसे सवाल नहीं बनते थे, जबकि मैं क्लास करता था, अच्छे से नोट्स बनाता था, और उन्हें रिवाइज कर लेता था। फार्मूले भी याद कर लेता था, फिर भी मुझसे सवाल बनते ही नहीं थे। समझ नहीं आता था कि कैसे स्टार्ट करूं। इसी चीज़ के लिए मैं आज यह वीडियो बना रहा हूं, ताकि मैं आपको समझा पाऊं कि कैसे इस...

चीज को टैकल करना है क्योंकि जब तक आप इस चीज से उबर नहीं जाते, जैसे इस चीज से ऊपर नहीं उठेंगे, तब तक आप नीट में सेलेक्ट नहीं हो पाएंगे। इसलिए आज की वीडियो काफी महत्वपूर्ण है। इसे अंत तक देखना, क्योंकि मैं अच्छे से यहां पर तीन उदाहरण के साथ आपको समझाऊंगा कि कैसे किसी भी प्रश्न को आपको टैकल करना है, चाहे वो कितना ही कांसेप्चुअल प्रश्न क्यों न हो। अब किसी भी प्रश्न को सॉल्व करने के लिए, चाहे वो फिजिक्स का हो या फिर फिजिकल का, आपको...

There are two important things: one is information, and the other is the approach to solve the question. We will discuss the approach in this video. First, let’s talk about what information you should know. Listen carefully so that the next time you go to solve a question, keep these things in mind and be ready. You should definitely know these things; only then will you be able to solve the question further through the approach. First, in the information, you need to know about...

You should know all the formulas of the chapter. You need to understand when to apply each formula and for which case it is applicable. You should also know the meaning of each term in that formula. These three things are very important. Additionally, you should have a clear understanding of the concepts taught by the teacher in that chapter. This is because you will decode the points written in theory and the text presented in your questions through those concepts.

You will find that whenever a question mentions a ball being dropped, you know that the initial velocity is zero. Similarly, if the voltage is not specified as RMS or average, you should assume it to be RMS. You need to be aware of all these points, as they are concepts that will help you decode the questions and provide your answers accordingly.

To understand what a good question has provided, you will then be able to approach it. Now, let's look at the main topic of the video: how to approach any question, regardless of what it is. The first and most important thing is to read the question carefully. If you read the question well, half of your work is already done. For example, if I show you through an example, any question that comes in front of you...

है जो बच्चे गलती करते हैं, वो यह है कि कभी वे पढ़ना सीखते नहीं। क्योंकि होता क्या है कि बच्चों ने देखा होता है कि क्लास में टीचर प्रश्न पढ़ते हैं, वो डिकोड करके बताते हैं कि यह यह दिया गया है और फिर वो दिए गए के मदद से हल कर लेते हैं। खुद से कभी प्रश्न पढ़ना नहीं सीखते। कभी भी आपको प्रश्न को इस तरीके से नहीं पढ़ना है कि यह टॉय कार एक चार्ज क्यू के साथ एक घर्षण रहित क्षैतिज सतह पर चलती है। ऐसे नहीं पढ़ना चाहिए।

You need to read the questions in parts from the start to the end, with a maximum of three to four words at a time. Understand what is being said in those parts. If you are a beginner, you should either write down what is given. If you are unable to form questions at all, write down what is given so that you have it in front of you. If you are at a slightly better level, you can underline the important parts, which is a much better way to study.

This is because you don't have time to write during NEET. If I show you this, the question in front of you is a long question. It is important to mark it well. So, how will we read it and how will we mark it? As you can see, the first thing they mentioned is that this is a toy car with a charge. Just read that much: charge. So, how much charge is there? I have marked it here. Let's move on.

Frictionless horizontal plane is frictionless; I have marked the plane here. A surface under the influence of a uniform electric field is uniform; there is no problem with that. I have marked it as E. Due to the force q, how much force is acting here? The force q is acting here. Its velocity increases from 0 to 6 meters per second in a one-second duration, which means that due to the force acting, its velocity increases.

कर रही है 0 मीटर प्रति सेकंड से 6 मीटर प्रति सेकंड तक। कितने ड्यूरेशन में? 1 सेकंड के ड्यूरेशन में। इतना मैंने मार्क किया, समझ भी लिया सवाल को और अच्छे से यहां पर हाईलाइट कर लिया। उस समय, विद्युत क्षेत्र का दिशा उलट दिया गया। ठीक है, रिवर्स। मैंने मार्क कर लिया ताकि मुझे याद रहे किसको रिवर्स किया गया है, विद्युत क्षेत्र के दिशा को। कार जारी है।

Move for two more seconds. Okay, for two more seconds, the car will move forward under the influence of this field, which was reversed. The field will influence it for two seconds more. The average velocity and the average speed of the toy car between 0 to 3 seconds are respectively. So finally, it was asked what the average velocity and average speed are for the duration from 0 to 3 seconds. As you can see, in the first second, it moves from 0 to 6 meters.

After the speed increased per second, the electric field was reversed, and then it continued for another 2 seconds, so the duration here was 3 seconds. In that same 3-second duration, you are asked about the average velocity and average speed. We have understood this concept. If you read the question in this way and mark it, half of your work is done here. Now, how to approach the next part is very important. Let me explain that to you.

बार, आपने ये दोनों स्टेप कंप्लीट कर लिया, उसके बाद आप क्या करोगे? देखोगे कि क्या मुझसे पूछा गया है, और उसके बाद प्रोसीड करोगे। मतलब कि आप पीछे से क्वेश्चन को सॉल्व करना स्टार्ट करोगे और देखोगे कि मुझसे क्या पूछा गया है। मेरे पास क्या-क्या चीजें गिवन हैं, और उसके अकॉर्डिंग कौन सा एप्रोप्रिएटनेस लेवल पे हो। तो जब तक आप इस अप्रोच को, जो मैं यहां बता रहा हूं, अप्लाई नहीं करोगे, बहुत सारे क्वेश्चन प्रैक्टिस नहीं करोगे, तब तक आपसे क्वेश्चन सॉल्व नहीं होगा।

You can go to the memo pad for starting, where you will find the concept building section in physics. In this section, you will find many basic formula-based questions. Here, you will learn how to apply the formulas and concepts repeatedly using the same approach. You will understand how to reach the final answer, how to apply the approach, how to start the question, and how to conclude it.

करता हूं। और ये करने के बाद, जब आप पीवा के सवाल सॉल्व करने जाएंगे, तो आपसे वहां आसानी से सवाल बनने लगेंगे। अगर आप बिगिनर नहीं हैं, तो आप अपने हिसाब से डिफिकल्टी लेवल भी वहां बदल सकते हैं। फॉर्मूला याद करने के लिए, आप वहां फ्लैश कार्ड्स का उपयोग कर सकते हैं, जिसमें आप फॉर्मूला बनाकर उसे याद कर पाएंगे। खुद से बायोलॉजी और केमिस्ट्री के लिए, आपको यहां एनसीईआरटी की हर एक लाइन से जुड़े 30,000 से अधिक सवाल मिल जाएंगे।

Claim that in NEET 2024, questions from Biology worth 360 marks, Physics worth 164 marks, and Chemistry worth 144 marks came from this Elite Plan. The proof document for this will be available in the description, where you can verify it yourself. In this, you also get part tests with a wonderful feature that allows you to select only the chapters you have completed and take part tests specifically for those chapters. Currently, two part tests are available for free.

So you can definitely go and give it to them and check the level. Lastly, you can find the Brahmastra revision magazine here, which includes key points of chemistry and mind maps of physics for quick revision. Additionally, there is an analysis section that presents around 35 to 40 important questions created after analyzing the last five years, through which you can grasp the important knowledge and concepts of all the chapters.

रिवाइज कर सकते हो। एलाइट प्लान में एनरोल करते ही आप इनके डाउट क्लीयरेंस ग्रुप में आ जाओगे। यह प्लान इंग्लिश और हिंदी मीडियम दोनों बच्चों के लिए उपलब्ध है। चाहे आप नीट 2026 की तैयारी कर रहे हों या फिर आप ड्रॉपर हों, दोनों ही इस बैच को ले सकते हैं। ड्रॉपर्स के लिए एक अच्छा ऑफर है कि 50 प्रतिशत डिस्काउंट मिलेगा, अगर आप वहां अपने स्कोर कार्ड को दिखाते हैं। इसका लिंक आपको डिस्क्रिप्शन में मिल जाएगा और एक्स्ट्रा...

You can use my code A300 for discounts. Now, let's move forward in the video. As I look here, I was asked two things: average velocity and average speed. As soon as you see that I was asked this, you might wonder what I know about these two concepts. For example, if I say average velocity, it is related to...

The first formula that comes to your mind is total displacement by total time. Alright, so you have written that formula down here. You don't need to do anything else; you just need to focus on one thing at a time. So, you have written the formula. Similarly, if I ask you about average speed, a formula comes to your mind: total distance by total time. You have noted that formula down here as well. You're not thinking about anything else; you are just writing it down.

We are gradually proceeding with the download. Now, you see that in this formula, what two things you have written, what do you not have? For example, do you have the total time? Yes, you do, which is given as 0 to 3 seconds, meaning you have a total time of 3 seconds. Do you have the total displacement? No, you do not. This means you will first need to find the total displacement before you can calculate the average velocity. So now, you...

The average velocity has been calculated. Now you need to focus on how to find the total displacement or total distance. If I can calculate both of these, then I will get my answer. Here you have thought that I require three things: total time, which we know; total displacement; and total distance, which we need to calculate. As I mentioned, the total time is given as 3 seconds, so we will not think about that.

We have eliminated it from our minds. Now we are only thinking about total distance and total displacement. Don't think about why I took an easy example; I am taking this example to explain to beginners so that they can relate to it. I have also included some good questions for later, so do check those out. So, what we have finalized is that we need to calculate total distance. However, your mind might not be functioning well on how to proceed further. Whenever this happens...

सिचुएशन आपके सामने आए, तो आप सोचें कि मेरे पास क्या-क्या दिया गया है। ठीक है, जो दिया गया है, उसे एक बार देखिए। आप यह सोचें कि मेरे पास यह है और मुझे क्या निकालना है। फिर उसके अनुसार आप फॉर्मूला सोच पाएंगे। जैसे कि अगर आप यहां जाओगे, तो ऊपर जाओगे। अगर मैंने यहां पर लिख दिया, तो आपके पास एक इनिशियल वेलोसिटी दी गई थी, जो कि 0 मीटर प्रति सेकंड थी। फिर वह 6 मीटर प्रति सेकंड तक बढ़ गई थी। मतलब, फाइनल वेलोसिटी आपके पास है और ये...

होने में कितना टाइम लगा था? 1 सेकंड का टाइम आपके पास लगा था। ठीक है, दो फेज यहां पर हो रहे हैं; एक 1 सेकंड का फेज है और फिर 2 सेकंड का फेज है। तो हम यहां पर एक-एक करके बात कर रहे हैं। 1 सेकंड के टाइम में 0 से 6 मीटर प्रति सेकंड की स्पीड बढ़ी थी। अब आपको निकालना क्या है? यहां पर जो यह इंक्रीज हुई है वेलोसिटी में, उसमें कितना डिस्टेंस चला? यह आपको निकालना है। तो आपको सोचना है कि अगर मेरे पास ये चीजें गिवन हैं और ये निकालना है, तो मैं कौन सा...

फॉर्मूला लगा सकता हूं। जैसे ही आप ये देखते हैं, तो आपके दिमाग में तीन फॉर्मूले आते हैं। ठीक है, गति का समीकरण है: v = u + at, s = ut + 1/2 at², और यह वाला फॉर्मूला ठीक है। लेकिन आप देखते हैं कि मुझे s निकालना है। तो अगर मुझे s निकालना है, तो मैं यह फॉर्मूला तो बिल्कुल नहीं लगा सकता हूं। तो ये मेरे दिमाग से एलिमिनेट हो गया। अब मेरे सामने हैं दो फॉर्मूले: एक s = ut + 1/2 at² और एक v² - u² = 2as। लेकिन मैं देख रहा हूं कि दोनों ही फॉर्मूले से अगर मुझे s...

If I need it, I will have to put the acceleration here first. I have the other things, but I don't have the acceleration. So, my mind has shifted away from distance; now my focus is on acceleration. I need to calculate acceleration first, and then I will find 's'. So, what formula comes to your mind for acceleration? a = (v - u) / t, where final velocity minus initial velocity is divided by time. You know that v is six, the initial velocity is zero, and the time is one.

You have the acceleration of 6 meters per second squared. Once you have this, you can plug it into either of the formulas, and your distance (s) will be solved. So, in a duration of one second, the distance covered comes out to be 3 meters. However, this calculation is only for one second. Now you need to solve for the next two seconds as well. For that case, write down the given information again. So, what do you have as given now?

The 2-second phase indicates that the initial velocity you will have is 6 meters per second. So, you have written 'u' here. Now, how much time do you have? You have a time of 2 seconds, so you have also written the time here. Do you know the acceleration? You know that it is the same force, just applied in the opposite direction, so the acceleration will be opposite. Now, this concept is something you...

If you can write here, then your acceleration has reversed; only the sign will change here, so your acceleration becomes -6 meters per second squared. Now you have three things given again, and you need to find what 's' is; there is a question mark here. So then you will think about which formula you can use. This formula will not work; neither of these formulas can be used, but you can see that you do not have the final velocity here.

In the first situation, if you cannot use this formula this time, then you have only one formula left that you can use. This one, in which you will keep u, time, and acceleration, and you will solve it. After solving, your answer will come out to be 0 meters. Alright, you know that the s that is solved here is the displacement. So, it needs to be stated that the displacement is 0 meters. This means that the total displacement here is...

पे हुआ वो हो गया 3 मीटर का। क्यों? क्योंकि यहां से पहले एक सेकंड में वो यहां तक पहुंचा, 3 मीटर की दूरी कवर करने के बाद। लेकिन अगले 2 सेकंड में वो वापस घूमकर यहीं आ गया। तो डिस्प्लेसमेंट जो था, इनिशियल लेवल से, वो बस 3 मीटर का हुआ है। तो डिस्प्लेसमेंट आपके पास आ गया 3 मीटर का। टाइम आपके पास था, तो टोटल 3 सेकंड का। तो एवरेज वेलोसिटी निकालने जाओगे, तो 1 मीटर पर सेकंड आ गया। ऑप्शन जाओगे देखने, तो एलिमिनेट कर सकते हो। तो यहां पे आपको दिख...

is that at 1 meter per second, only options B and D are available, so these two options have been eliminated. Now, it could either be 3 meters per second or 3.5 meters per second. You need to determine which is the correct answer for average speed. To do this, you can check the total distance traveled. You observed that 3 meters were covered in the first second, and since the acceleration did not change, in the next second, it would have traveled another 3 meters ahead, and then the displacement...

Because it is zero, then in the next second, it must have come back 3 meters behind; only then can the displacement be zero. This is basic. Those who have a clear understanding of the concept will find it very easy to grasp. So, I have drawn a diagram here. Accordingly, your distance comes to 9 meters, and your average speed is 9/3, which means 3 meters per second. In this way, what you observed is that we kept eliminating things. The only thing we needed to find was what we focused on.

I focused on it and solved it. When it came up, we put in the upper part that we needed to extract, and then we got the final answer. You just have to do this. If someone says, Brother, this is a very long method, I know that it can be done in an easier way. I'm just explaining here how you need to approach things one thing at a time. You can also do this using the graph method.

Then what I said is that the acceleration is the same, so in one second, it will go as far forward as it will go back in the next second. The acceleration is 6 meters per second squared, which means that in one second, its speed is increasing by 6 meters per second. And if you oppose it, then in one second, its speed will decrease at the same rate. That's why you saw that in the first second, its speed became 26 meters per second. When it was reversed, in the next second, it went from 6 to zero.

will happen, and then in the next second, it would have returned, developing a speed of 6 meters per second but in the opposite direction. So, it has covered the same distance in one second because the acceleration here is the same. So, no matter what question comes your way, always look at what is being asked and what is given. You should use the best formula that relates to this and start solving the question using that formula. Now, the next...

The question is approached and solved in the same way. First, you need to read the question carefully and mark it. Half of your work is done right here. A block of mass m is released on the top of a smooth inclined plane. So, what kind of plane is this? The inclined plane is smooth, meaning there is no friction acting on it. Its length is given as x.

हुआ है और इसकी इंक्लिनेशन कितनी है, थीटा है ये भी बता दिया गया है प्रश्न में। हॉरिज़ोंटल सतह रफ है। हॉरिज़ोंटल सतह जो है, वो आपकी रफ है, मतलब यहां पर फ्रिक्शन लगेगा। अगर ब्लॉक एक दूरी d पर चलने के बाद रेस्ट में आ जाता है, तो इसका मतलब है कि जब ब्लॉक यहां पर मूव करता है, तो d दूरी मूव करने के बाद वो रेस्ट पर आ जाता है। ठीक है, तो मतलब फाइनल वेलोसिटी यहां पर ज़ीरो हो रही है, ये भी हमने पता कर लिया है।

Here, we moved and also found out what was asked. Then, the coefficient of friction between the block and the surface is what we need to determine. We have been asked how much the coefficient of friction will be. Since we have been asked about it, we will think about everything related to it. Because it has been mentioned, we have some discussion regarding friction, and the final velocity is zero. All these points have been discussed, so we need to think about 'm' first, just as we have...

When we thought about average velocity and average speed, we considered the concept of friction. If we were asked about it, a formula comes to mind: friction = μ. So, we wrote down that formula, not knowing if it would give us the answer. We wrote friction = μn. Now, we needed to find μ, so we rearranged it and found that μ = friction / n. Now, we should consider what we have and what we need to find.

होगा तो हमें पता है कि N हम निकाल सकते हैं यहां पे, क्योंकि हॉरिज़ेंटल सरफेस पे जब ब्लॉक आएगा, तो यहां पे जो N होगा, वो ऊपर लग रहा होगा। और इस पे जो वेट लग रहा होगा, ग्रेविटी के कारण, वो होगा mg1 के बराबर। ये सिंपल मैथ है। जिसने भी फिजिक्स पढ़ी है, उनको समझ में आ जाएगा। तो N यहां पे mg1 के बराबर है। आपने यहां पे वक्त ठीक है। तो आपके पास जो अब फॉर्मूला आया, वो आया = फ्रिक्शन / mg1 पे। देखा था, टाइम आपके पास था, आपको बस वहां पे डिस्प्लेसमेंट और डिस्टेंस चाहिए थे।

निकालना था तो सेम, अब हम लोग फोकस करेंगे कि फ्रिक्शन कैसे निकाला जाए। तो हमें समझ नहीं आ रहा है कि कैसे निकालें। तो हम लोग देखेंगे, गिवन क्या है। तो अगर आप गिवन ऊपर जाएंगे, तो आपको कुछ ऐसा खास गिवन मिलेगा नहीं। तो आपको जब भी ऐसा कुछ गिवन ना मिले, डिजिट्स के फॉर्म में, न्यूमेरिकल फॉर्म में, तो आप हमेशा देखेंगे कि कोई ऐसी लाइन छुपी होगी, जिसके जरिए आप वहां पर कोई इक्वेशन बना सकते हो। तो यहां पर जब आप ध्यान से देखते हैं, तो आपको ये लाइन देखने को मिलेगी।

कोई ब्लॉक आराम करता है जब वह एक निश्चित दूरी d को क्षैतिज सतह पर चलने के बाद रुक जाता है। इसका मतलब है कि जो भी ऊर्जा उसके पास थी, वह सभी घर्षण के कारण खो गई है। घर्षण के कारण काम में चली गई। इसलिए आप यह मान सकते हैं कि यहां जो भी ऊर्जा है, वह घर्षण द्वारा किए गए काम के बराबर है। आपको एक समीकरण पता है, जिसे आप पढ़ते हैं: काम-ऊर्जा प्रमेय।

I will not read here; it will become boring. If you have read Delta E equal to work done, you know that the change in kinetic energy is such that the final energy, the final velocity is zero. So, what will the final kinetic energy be? It will be zero. If you know the initial kinetic energy, you can equate it to the work done by friction, and you can find the final answer for the value of friction. Now you just need to see if you understand up to this point.

I need to determine what my current requirement is. What I need now is to find out how much initial kinetic energy there is. If you go up and see that at this point, if I can find out the initial kinetic energy, then my answer will come here. At this point, the kinetic energy will be equal to the potential energy here because if you take this as your reference level, all the energy, the potential energy, will convert here.

जब काइनेटिक एनर्जी में जाएगी, तो जो मैं इसे h हाइट मानता हूं, तो mgh² करना होगा। सबसे पहले, आपको दिख रहा है कि अगर आप अच्छे से त्रिकोण बनाते हैं, तो यह आपका h है और यह x है। तो आपको दिख रहा है कि जो x है, उसका θ होगा, वही यहां पर h के बराबर होगा। ठीक है, यह बुनियादी गणित है। अगर x है, तो यह x का θ है और यह x का θ है, और वही आपका x का θ है, जो कि h के बराबर है। इसलिए आपने h को यहां पर सब्स्टीट्यूट कर दिया। इसका मतलब है कि mgs³, वही आपकी काइनेटिक एनर्जी इनिशियल है।

So, you substituted everything there. First, you wrote that the initial value will be mgh2, then you equated h to xs3. After that, you equated it to -mgs3 * d. The minus sign is there because it goes in the opposite direction. Then, this minus and minus will cancel out when you solve it, and the friction will come into play. When you put this back up, it will be mgm6 th / d. This is how you substituted. You saw how we did it.

We first need to see which formula to choose. Then we looked at how to input initial kinetic energy. After that, we noticed that we don't have h, so we substituted that. You have to focus on one thing at a time while substituting the variables, and that's how you reach the final answer. This is all you need to do in physics. Now, let's take a look at one last question. What will we do first? First, we will read this question carefully and mark it.

Let's take a look at what important things we can use. First, we need to see how to read properly. We need to read two or three words clearly at a time. We have two identical capacitors, C1 and C2. If there is a diagram, we will also look at it together. So, C1 and C2 are here with equal capacitance, which means that C1 = C2. We can consider this as C, as shown in the figure, just like in the circuit displayed.

Terminals A and B of the key K are connected to charge capacitor C1. Here, a key is provided, which we are using to charge C1 with a battery of EF volts. The voltage of the battery is V, and we are charging C1 through it. Now, disconnecting A and B, we have disconnected terminals A and B. After that, terminals B and C are connected.

Due to this, what will be the percentage loss of energy? What is being asked is what will be the percentage loss of energy when we do this: first, we connected A and B, then it got charged. After that, when we connected B and C, and then disconnected it, the first thing that was asked is the percentage loss of energy. You know how to calculate energy loss. Energy loss means something that was initially high has decreased. So, the initial...

Energy loss is calculated by taking the initial energy and subtracting the final energy. Whatever you get from this subtraction will be your loss. So, we can see how much energy loss occurred by using the formula: initial energy minus final energy. I'm not talking about percentages right now; I'm just explaining how to calculate energy loss. So, this is the method we will use. Now, we will focus on what we need: we need the initial energy and the final energy.

If we can extract energy from both of these individually, then we can finally determine energy loss as well. So how will we calculate the initial energy? Initially, what happened was that A and B were connected, and the circuit was like this. The energy stored in this will be in the capacitor, and that will be your initial energy. You know that the energy stored in a capacitor is given by 1/2 C squared. So, the initial energy will be...

Your initial energy will be 1/2 c, because it is not connected, so it won't store any charge. Therefore, you will have an initial energy of 1/2. Let's look at the final energy, which is important. It might be that you cannot even think of the final energy. This happened to me as well; I didn't come up with this question the first time. After I saw the solution, I learned it, and this question repeats very often. That's why it's important.

However, mostly you should know how to approach any question. When you think about final energy, you can see that there are two capacitors here. So, you will need to take C net here, and then you will also need to take V net. The formula that will be formed is 1/2 C net * (V net) squared. Here, what will C net be? You can see that when this circuit is connected, it will be in parallel.

In parallel, the equivalent capacitance (C_net) is how much? If you add them, it will become 2C. Now, how do you find V_net? To find V_net, you need to know that V_net will be equal to the total charge divided by the total capacitance. So, you have written that down. You need to think about each thing step by step. We have already found C_net to be 2C. Now, we need to think about V_net. How much will V_net be? It will be the total charge divided by the total capacitance. What will the total charge be?

You saw that initially there was a charge, and you put your net voltage here, so it came out to be CV1/4 final energy. Now, if you want to calculate the loss, first calculate the loss percentage by dividing it by the initial value; this is basic math. So, you noticed that the initial energy was 5 because I am not considering the capacitors; that will be cut off. So, the initial was 0.5, and the final was 1/4, which means it was 25, and the initial...

To calculate the percentage, we divide by 5 and then multiply by 100, which gives you 50. So, you had a loss of 50 percent here. This may not be solved in your first attempt, but at least try to solve it up to this point; this is what I expect from you after this video. The basic thing we learned is that whenever you solve a question, consider what my requirement is and think only about that at that moment.

If you think for a moment about how I can reach the final answer, you will realize that the question will never be solved. Just like I did with every question, I am only thinking about what I need to extract from myself. I am focused solely on that aspect, and afterward, I am looking at what the requirements are, what the demands I have are, and what things I possess. Then, I am putting those together to extract what I need. After that, I am looking at what remains for me to put forward next.

Then I am focusing on it and proceeding in this way. So, always focus on one thing at a time, and your questions will get solved. Alright, make sure to review the approach I mentioned once again and try to incorporate it into your question practice. Because until you use the approach for question practice, you won't start solving questions. I hope you liked the video.

Please like this video, subscribe to the channel, and share it with your friends. Alright, bye! See you in the next video. Until then, take care.

Solve Any NEET 2025 Numerical With This Trick😎| 690+ In NEET 2025| Physics & Physical chemistry 🌟

Avinash Sharma

니트 지원자를 위한 문제 해결의 어려움 해결

많은 NEET 지원자들은 수업에서 개념을 이해했음에도 불구하고 문제를 푸는 데 어려움을 겪습니다.

이러한 어려움을 해결하는 열쇠는 공식과 그 적용 가능성을 알고, 배운 개념을 이해하는 데 있습니다.

이 동영상은 문제 해결에 효과적으로 접근하기 위해 문제를 주의 깊게 읽고 해독하는 것이 중요하다는 점을 강조합니다.

물리학 문제 해결을 위한 효과적인 전략

문제를 작은 부분으로 나누어 읽으면 요점을 이해하는 데 도움이 됩니다.

전하, 힘, 지속 시간과 같은 중요한 정보는 빠르게 참조할 수 있도록 표시해 두는 것이 중요합니다.

이러한 접근 방식을 연습하고 개념 정리를 위해 메모장을 사용하면 물리학의 문제 해결 능력을 향상시킬 수 있습니다.

엘리트 플랜은 생물학 및 화학에 대한 NCERT와 연결된 30,000개 이상의 문제를 통해 NEET 준비에 대한 포괄적인 접근 방식을 제공합니다.

이 플랜은 생물학 360점, 물리학 164점, 화학 144점으로 2024년 NEET에 합격하는 데 기여했다고 주장합니다.

이 플랜은 파트 테스트, 개정판 매거진, 오답 정리 그룹을 제공하며, 중도 탈락자에게는 50% 할인을 제공합니다.

초보자를 위한 간단한 예제를 사용하여 총 거리와 변위를 계산하는 데 중점을 둡니다.

초기 속도는 0m/s이며 1초에 걸쳐 6m/s로 증가하며 이 시간 동안 이동한 거리를 계산해야 합니다.

가속도는 6m/s²로 처음 1초 동안은 3m의 거리로 이어지며, 두 번째 단계에서는 2초 동안 -6m/s²의 역가속이 발생하므로 거리를 계산할 때 다른 접근 방식이 필요합니다.

물체가 처음 1초 동안 이 거리를 이동한 후 다음 2초 동안 시작 지점으로 돌아오므로 물체의 변위는 3미터입니다.

총 소요 시간은 3초이므로 평균 속도는 초당 1m입니다.

총 이동 거리는 9미터이므로 평균 속도는 초당 3미터입니다.

거친 표면의 블록에 대한 마찰 계수 결정하기

블록은 거친 수평 표면에서 거리 d를 이동한 후 정지하며, 이는 최종 속도가 0임을 나타냅니다.

블록과 표면 사이의 마찰 계수(μ)는 μ = 마찰 / N 공식을 사용하여 결정할 수 있으며, 여기서 N은 mg1과 같은 정상 힘입니다.

일-에너지 원리를 적용하여 초기 운동 에너지를 마찰에 의해 수행되는 일과 동일시하여 마찰 값을 구하고 궁극적으로 μ를 결정할 수 있습니다.

운동 에너지 및 커패시터 충전에 대한 이해

운동 에너지는 mgh² 공식을 사용하여 계산되며, h와 x는 각도 θ를 통해 관련됩니다.

초기 운동 에너지는 -mgs³ * d와 같으며, 음의 부호는 반대 방향을 나타냅니다.

두 개의 동일한 커패시터인 C1과 C2를 충전하는 과정을 설명하며, 커패시터에 저장된 초기 에너지에서 최종 에너지를 빼서 에너지 손실 비율을 계산합니다.

커패시터가 연결되지 않았으므로 시스템의 초기 에너지는 1/2입니다.

최종 에너지는 커패시터가 병렬로 연결되어 있기 때문에 1/2 C_net * (V_net)^2 공식을 사용하여 계산되며, C_net은 2C입니다.

손실률은 초기 에너지와 최종 에너지를 비교하여 결정되며, 50%의 손실이 발생합니다.