이온성 고체 결정에서 이온은 바둑판 모양으로 배열되어 인력을 극대화하고 반발력을 최소화하며, 양이온은 음이온보다 작습니다.

### 이온 결정 구조: 이온 및 이온 반경의 배열
* 🔵 이온성 고체 내의 이온은 **쿨롱 힘에 따라 인력을 최대화**하고 반발력을 최소화하는 방식으로 배열됩니다.
* 🏰 가장 안정적인 배열은 **모든 양이온이 음이온으로 둘러싸인 바둑판 패턴**이며, 그 반대의 경우도 마찬가지입니다.
* 🛡 이 배열은 **3차원 격자 구조**로 시각화할 수 있습니다.
* 📏 이온성 고체에서 **이온의 크기**는 핵의 인력과 전자 구름의 반발력 사이의 균형에 의해 결정됩니다.
* 예를 들어, 루비듐 브롬화물(RbBr)의 경우 **루비듐 양이온이 브롬화물 음이온보다 작은 이유**는 루비듐 핵이 브롬화물 핵보다 전자의 외피를 더 많이 끌어당기기 때문입니다.
* 🔵 브롬화 루비듐의 입자 모델에서 **브롬화 음이온은 루비듐 양이온보다 크며, 상대적인 크기를 반영하는 패턴**으로 배열됩니다.

[Instructor] In this video, we're gonna think about how ions will arrange themselves when they form solid crystals. When they form these lattice structures. So just in very broad brush terms, let's say that we have a bunch of this white cation, and we have a bunch of this green, or this blue-green anion. So let's say they're in a one-to-one ratio. How will that look? How will the solid look, if you were to take a two-dimensional slice of it? To imagine that, we can draw what we could call particulate models. We're just imagining a two-dimensional slice of the solid, and we're just drawing these ions as particles. Would it look something like this, where maybe the positive ion is all on one side, and then the negative ion is on the other side, is on the bottom if we were to take a slice? Would something like this make sense?

Or maybe it's random. Maybe you have a positive there, and then you have some
negatives right over there. And then, maybe you have
a positive and a positive, and then a positive right over there. And then maybe you have some
negatives right over there. Would this be a reasonable configuration, as they form these ionic bonds? Well, when we think about Coulomb forces, we know that like charges repel each other, and unlike charges, or opposite
charges, attract each other. And so, when these ionic solids form, they're unlikely to form in this way, or even in this way,
because they're gonna form in a way that maximizes
the attractive forces and minimizes the repulsive,
the repelling forces. And so what would be an
arrangement that does that? Pause this video and think about it. Well, all the positive charges are gonna try to get as close as possible to the negative charges
and as far as possible.

from other positive charges. And the same thing is going to
be true of negative charges. They're gonna try to get as far away from other negative charges as possible, and as close to other
positive charges as possible. So the arrangement that
you are likely to see is going to look something more
like a checkerboard pattern. So it may be a positive there, a positive there, a positive there, a positive there, and a positive there. These are all the same ion. I'm not drawing it perfectly;
they'd be the same size. And when you do these
two-dimensional representations, these particulate models, it is important to get the size right, 'cause we're gonna think
about that in a second. And then the negative
charges would be in between. So notice, in this configuration, every negative is surrounded by positives, and every positive is
surrounded by negatives. So it's maximizing the attractive forces, and it's minimizing the repulsive forces.

And if you were to think
about it in three dimensions, you would have a lattice structure that looks something like that. And we have seen this in other videos. Now another interesting
thing to think about is the size of the ions
that form that ionic solid. Let's say we wanted to
deal with rubidium bromide. Rubidium bromide. What would this look
like if I were to draw it in a two-dimensional
particulate model like this, and I wanted to make the
size roughly comparable to what we would see between
the rubidium and the bromide? Pause this video and think about that, and I'll give you a little bit of a hint. It might be useful to look at this periodic table of elements. All right, if we were to
separate this out into its ions, it is a rubidium cation,
and a bromide anion. Now a rubidium cation,
it has lost an electron.

So even though it still has 37 protons, its electron configuration now
looks like that of krypton. Now, the bromide anion, even
though it only has 35 protons, it's going to gain an electron
to become a bromide anion, and it also has an electron
configuration of krypton. So both of these have the
same number of electrons, but rubidium has two more
protons than bromide does. And so the rubidium is going to attract that outer shell of electrons, that fourth shell of electrons, more than the bromide nucleus is going to. And so, the rubidium in this example is going to be smaller than the bromide. And so if I were to draw
one of these diagrams, it would look something like this. Let me draw the bromide first. So I have a bromide anion, I
have another bromide anion, another bromide anion,
maybe I have a bromide anion

right over here, bromide anion over there, maybe a few more. Make 'em a little bit. If I
was doing this with a computer, I would make them all the same size. So these are our bromide anions. And then your rubidium cations
would be a bit smaller. And so, our particulate
model right over here might look something like this. We wanna make it clear that the cation is a bit smaller than the anion. It would arrange, it would likely arrange in a pattern that looks like this. And notice, I am trying to make the sizes roughly accurate to show that the cation is indeed smaller than the anion. Although it wouldn't be
dramatically smaller. Remember, they have the
same number of electrons. And they don't have that dramatically different number of protons. And this is just a very rough drawing. If they were dramatically different, you might show that in
the sizes on this diagram.

Representing ionic solids using particulate models | AP Chemistry | Khan Academy

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이온은 격자 구조를 통해 고체 결정을 형성하며, 양이온과 음이온의 비율에 따라 배열이 결정됩니다.

입자 모델은 고체의 2차원 조각과 그 안에서 이온이 어떻게 배열되는지 상상하는 데 사용됩니다.

이온의 배열은 같은 전하가 서로 밀어내고 반대 전하가 서로 끌어당기는 쿨롱 힘의 원리를 기반으로 합니다.

이온성 고체는 인력을 극대화하고 반발력을 최소화하는 방식으로 형성되어 양전하와 음전하가 바둑판 모양으로 배열됩니다.

이 구성에서 양전하들은 서로 최대한 멀리 떨어져 음전하와 가까워지고, 음전하들은 양전하로 둘러싸여 있습니다.

2차원 표현에서 이온의 크기는 이 배열에서 고려해야 할 중요한 요소입니다.

이온 고체 형성: 인력 최대화 및 반발력 최소화

이온성 고체는 인력을 극대화하고 반발력을 최소화하는 격자 구조를 가지고 있습니다.

고체 내 이온의 크기는 전자 구성과 양성자와 전자 사이의 균형에 의해 결정됩니다.

브롬화 루비듐의 경우, 브롬화 음이온보다 양자가 두 개 더 많은 루비듐 양이온이 전자의 외피를 끌어당겨 고체 내 이온의 크기를 결정합니다.

입자 모델에서 브롬화물과 루비듐 이온의 상대적 크기

브롬화 음이온은 루비듐 양이온보다 크기 때문에 입자 모델에서 특정 배열을 형성합니다.

두 이온의 크기 차이는 양성자와 전자의 수 차이 때문입니다.

이 다이어그램은 양이온이 음이온보다 작아 이온 화합물에서 상대적인 크기를 반영하는 방법을 보여줍니다.